There are 7 total marbles at the start (3 red, 4 blue) The chance of the first marble being blue is 4/7. Now we only have 6 marbles in the bag (3 red and 3 blue) The chance of the second marble being blue is 3/6. To find the odds of both being blue we multiply the two probabilities. 4/7 * 3/6 = 12/42 = 2/7, or about 28.6%. A bag contains 3 red marbles, 2 blue marbles, and 5 green marbles. What is the probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble? Algebra Linear Inequalities and Absolute Value Theoretical and Experimental Probability
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A bag contains 3 green marbles, 3 blue marbles, and 4 red marbles, what is the probability that a red marble is randomly chosen, replaced, and then another red marble is randomly chosen the second pick? Algebra Linear Inequalities and Absolute Value Theoretical and Experimental Probability.. Question 1157705: A bag contains 3 red marbles and 4 white marbles. Two marbles are drawn in succession without replacement. Find the probability the first marble drawn is red and the second is white. Find the probability Both marbles drawn are red. Answer by math_helper(2459) (Show Source):
